2+4g-g2=g

Solution for 2+4g-g2=g equation:

2+4g-g2=g

We move all terms to the left:

2+4g-g2-(g)=0

We add all the numbers together, and all the variables

-1g^2+3g+2=0

a = -1; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-1)·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{17}}{2*-1}=\frac{-3-\sqrt{17}}{-2}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{17}}{2*-1}=\frac{-3+\sqrt{17}}{-2}
$