8=4(a+1)+8(a-1)

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Solution for 8=4(a+1)+8(a-1) equation: 



8=4(a+1)+8(a-1)

We move all terms to the left:

8-(4(a+1)+8(a-1))=0



We calculate terms in parentheses: -(4(a+1)+8(a-1)), so:

4(a+1)+8(a-1)

We multiply parentheses

4a+8a+4-8

We add all the numbers together, and all the variables

12a-4

Back to the equation:

-(12a-4)



We get rid of parentheses

-12a+4+8=0

We add all the numbers together, and all the variables

-12a+12=0

We move all terms containing a to the left, all other terms to the right

-12a=-12

a=-12/-12

a=1

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