2+3/(x+1)=6/(x+1)

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Solution for 2+3/(x+1)=6/(x+1) equation: 



2+3/(x+1)=6/(x+1)

We move all terms to the left:

2+3/(x+1)-(6/(x+1))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (x+1))!=0

x∈R



We calculate fractions


3x/((x+1)*(x+1)))+(-(6*(x+1))/((x+1)*(x+1)))+2=0

We calculate fractions


(3x*((x+1)*(x+1)))+2)/(((x+1)*(x+1)))+(*((x+1)*(x+1)))+2)+(-(6*(x+1))*((x+1)*(x+1)))+()/(((x+1)*(x+1)))+(*((x+1)*(x+1)))+2)=0



We calculate terms in parentheses: +(3x*((x+1)*(x+1))), so:

3x*((x+1)*(x+1))



We can not solve this equation

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