2(3k-1)=27

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Solution for 2(3k-1)=27 equation: 



2(3k-1)=27

We move all terms to the left:

2(3k-1)-(27)=0

We multiply parentheses

6k-2-27=0

We add all the numbers together, and all the variables

6k-29=0

We move all terms containing k to the left, all other terms to the right

6k=29

k=29/6

k=4+5/6

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