2+3(x-8)=11-5(x-4)

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Solution for 2+3(x-8)=11-5(x-4) equation: 



2+3(x-8)=11-5(x-4)

We move all terms to the left:

2+3(x-8)-(11-5(x-4))=0

We multiply parentheses

3x-(11-5(x-4))-24+2=0



We calculate terms in parentheses: -(11-5(x-4)), so:

11-5(x-4)

determiningTheFunctionDomain
-5(x-4)+11

We multiply parentheses

-5x+20+11

We add all the numbers together, and all the variables

-5x+31

Back to the equation:

-(-5x+31)



We add all the numbers together, and all the variables

3x-(-5x+31)-22=0

We get rid of parentheses

3x+5x-31-22=0

We add all the numbers together, and all the variables

8x-53=0

We move all terms containing x to the left, all other terms to the right

8x=53

x=53/8

x=6+5/8

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