(8v-1)(v-1)=0

Solution for (8v-1)(v-1)=0 equation:

(8v-1)(v-1)=0

We multiply parentheses ..

(+8v^2-8v-1v+1)=0

We get rid of parentheses

8v^2-8v-1v+1=0

We add all the numbers together, and all the variables

8v^2-9v+1=0

a = 8; b = -9; c = +1;
Δ = b2-4ac
Δ = -92-4·8·1
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-7}{2*8}=\frac{2}{16}
=1/8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+7}{2*8}=\frac{16}{16}
=1
$