2+2(7y-8)=-2(4y-2)+6y

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Solution for 2+2(7y-8)=-2(4y-2)+6y equation:



2+2(7y-8)=-2(4y-2)+6y
We move all terms to the left:
2+2(7y-8)-(-2(4y-2)+6y)=0
We multiply parentheses
14y-(-2(4y-2)+6y)-16+2=0
We calculate terms in parentheses: -(-2(4y-2)+6y), so:
-2(4y-2)+6y
We add all the numbers together, and all the variables
6y-2(4y-2)
We multiply parentheses
6y-8y+4
We add all the numbers together, and all the variables
-2y+4
Back to the equation:
-(-2y+4)
We add all the numbers together, and all the variables
14y-(-2y+4)-14=0
We get rid of parentheses
14y+2y-4-14=0
We add all the numbers together, and all the variables
16y-18=0
We move all terms containing y to the left, all other terms to the right
16y=18
y=18/16
y=1+1/8

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