7y+7-2(-3y-3)=5(y-1)

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Solution for 7y+7-2(-3y-3)=5(y-1) equation: 



7y+7-2(-3y-3)=5(y-1)

We move all terms to the left:

7y+7-2(-3y-3)-(5(y-1))=0

We multiply parentheses

7y+6y-(5(y-1))+6+7=0



We calculate terms in parentheses: -(5(y-1)), so:

5(y-1)

We multiply parentheses

5y-5

Back to the equation:

-(5y-5)



We add all the numbers together, and all the variables

13y-(5y-5)+13=0

We get rid of parentheses

13y-5y+5+13=0

We add all the numbers together, and all the variables

8y+18=0

We move all terms containing y to the left, all other terms to the right

8y=-18

y=-18/8

y=-2+1/4

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