2*(x-3)-4*(x+2)=2*(x-1)-20

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Solution for 2*(x-3)-4*(x+2)=2*(x-1)-20 equation: 



2(x-3)-4(x+2)=2(x-1)-20

We move all terms to the left:

2(x-3)-4(x+2)-(2(x-1)-20)=0

We multiply parentheses

2x-4x-(2(x-1)-20)-6-8=0



We calculate terms in parentheses: -(2(x-1)-20), so:

2(x-1)-20

We multiply parentheses

2x-2-20

We add all the numbers together, and all the variables

2x-22

Back to the equation:

-(2x-22)



We add all the numbers together, and all the variables

-2x-(2x-22)-14=0

We get rid of parentheses

-2x-2x+22-14=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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