If it's not what You are looking for type in the equation solver your own equation and let us solve it.
15x^2-27x=0
a = 15; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·15·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*15}=\frac{0}{30} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*15}=\frac{54}{30} =1+4/5 $
| 7s+12=5+4s | | 1/c+1/12+1/16=1/4. | | 7x=104−6x | | 3x-3=9-2x | | y/3+5=7 | | 7m+9=102 | | 4y+1=-2y-7 | | 10,5=z+2,5 | | (10+7)x(25-13=) | | x^2-5x+8=10 | | 100-y=2 | | 12+17=82-v | | 6n^-24n=0 | | 17r-15=9r+9 | | 11x+17=6x+57 | | 9x2+42x+24=0 | | 0.12=5t^2 | | 8x+x+7x=15+x | | 5(x-3)+7(x+2)=11 | | x+6/8=4 | | 6b+4=2b-12 | | 2x/7+4=7 | | x/2-5=6/3 | | x-54=3x | | x+(x/2)=42 | | 21x+1=34 | | x+(x÷2)=42 | | 3=6x-3=9 | | 6y+8=68 | | 3x2+5√5x-10=0 | | p-10=-2 | | 7x-4=7x |