2*(t-1)+3*(1-t)=4*(t-2)

Solution for 2*(t-1)+3*(1-t)=4*(t-2) equation:

2(t-1)+3(1-t)=4(t-2)

We move all terms to the left:

2(t-1)+3(1-t)-(4(t-2))=0

We add all the numbers together, and all the variables

2(t-1)+3(-1t+1)-(4(t-2))=0

We multiply parentheses

2t-3t-(4(t-2))-2+3=0


We calculate terms in parentheses: -(4(t-2)), so:

4(t-2)

We multiply parentheses

4t-8

Back to the equation:

-(4t-8)


We add all the numbers together, and all the variables

-1t-(4t-8)+1=0

We get rid of parentheses

-1t-4t+8+1=0

We add all the numbers together, and all the variables

-5t+9=0

We move all terms containing t to the left, all other terms to the right

-5t=-9

t=-9/-5

t=1+4/5