(4x+-6)/7=2

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Solution for (4x+-6)/7=2 equation:



(4x+-6)/7=2
We move all terms to the left:
(4x+-6)/7-(2)=0
We add all the numbers together, and all the variables
(4x-6)/7-2=0
We multiply all the terms by the denominator
(4x-6)-2*7=0
We add all the numbers together, and all the variables
(4x-6)-14=0
We get rid of parentheses
4x-6-14=0
We add all the numbers together, and all the variables
4x-20=0
We move all terms containing x to the left, all other terms to the right
4x=20
x=20/4
x=5

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