2(z-7)+6z=2(2z+7)+4

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Solution for 2(z-7)+6z=2(2z+7)+4 equation: 



2(z-7)+6z=2(2z+7)+4

We move all terms to the left:

2(z-7)+6z-(2(2z+7)+4)=0

We add all the numbers together, and all the variables

6z+2(z-7)-(2(2z+7)+4)=0

We multiply parentheses

6z+2z-(2(2z+7)+4)-14=0



We calculate terms in parentheses: -(2(2z+7)+4), so:

2(2z+7)+4

We multiply parentheses

4z+14+4

We add all the numbers together, and all the variables

4z+18

Back to the equation:

-(4z+18)



We add all the numbers together, and all the variables

8z-(4z+18)-14=0

We get rid of parentheses

8z-4z-18-14=0

We add all the numbers together, and all the variables

4z-32=0

We move all terms containing z to the left, all other terms to the right

4z=32

z=32/4

z=8

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