-5(4f-2)=2(5-10f)

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Solution for -5(4f-2)=2(5-10f) equation: 



-5(4f-2)=2(5-10f)

We move all terms to the left:

-5(4f-2)-(2(5-10f))=0

We add all the numbers together, and all the variables

-5(4f-2)-(2(-10f+5))=0

We multiply parentheses

-20f-(2(-10f+5))+10=0



We calculate terms in parentheses: -(2(-10f+5)), so:

2(-10f+5)

We multiply parentheses

-20f+10

Back to the equation:

-(-20f+10)



We get rid of parentheses

-20f+20f-10+10=0

We add all the numbers together, and all the variables

=0

f=0/1

f=0

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