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5r+6/6r=7
We move all terms to the left:
5r+6/6r-(7)=0
Domain of the equation: 6r!=0We multiply all the terms by the denominator
r!=0/6
r!=0
r∈R
5r*6r-7*6r+6=0
Wy multiply elements
30r^2-42r+6=0
a = 30; b = -42; c = +6;
Δ = b2-4ac
Δ = -422-4·30·6
Δ = 1044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1044}=\sqrt{36*29}=\sqrt{36}*\sqrt{29}=6\sqrt{29}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-6\sqrt{29}}{2*30}=\frac{42-6\sqrt{29}}{60} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+6\sqrt{29}}{2*30}=\frac{42+6\sqrt{29}}{60} $
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