2(z-6)=3(z+2)

Solution for 2(z-6)=3(z+2) equation:

Simplifying
2(z + -6) = 3(z + 2)

Reorder the terms:
2(-6 + z) = 3(z + 2)
(-6 * 2 + z * 2) = 3(z + 2)
(-12 + 2z) = 3(z + 2)

Reorder the terms:
-12 + 2z = 3(2 + z)
-12 + 2z = (2 * 3 + z * 3)
-12 + 2z = (6 + 3z)

Solving
-12 + 2z = 6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-12 + 2z + -3z = 6 + 3z + -3z

Combine like terms: 2z + -3z = -1z
-12 + -1z = 6 + 3z + -3z

Combine like terms: 3z + -3z = 0
-12 + -1z = 6 + 0
-12 + -1z = 6

Add '12' to each side of the equation.
-12 + 12 + -1z = 6 + 12

Combine like terms: -12 + 12 = 0
0 + -1z = 6 + 12
-1z = 6 + 12

Combine like terms: 6 + 12 = 18
-1z = 18

Divide each side by '-1'.
z = -18

Simplifying
z = -18