1/3(y+2)+3x=7x

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Solution for 1/3(y+2)+3x=7x equation: 


x in (-oo:+oo)

(1/3)*(y+2)+3*x = 7*x // - 7*x

(1/3)*(y+2)+3*x-(7*x) = 0

(1/3)*(y+2)+3*x-7*x = 0

1/3*(y+2)+3*x-7*x = 0

1/3*(y+2)+3*x-7*x = 0

3*x-7*x+1/3*y+2/3 = 0

1/3*y-4*x+2/3 = 0

1/3*y-4*x+2/3 = 0

1/3*y-4*x+2/3 = 0 // - 1/3*y+2/3

-4*x = -(1/3*y+2/3) // : -4

x = (-(1/3*y+2/3))/(-4)

x = (1/3*y+2/3)/4

x = (1/3*y+2/3)/4

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