2(z-5)-(4z-4)=-3z

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Solution for 2(z-5)-(4z-4)=-3z equation: 



2(z-5)-(4z-4)=-3z

We move all terms to the left:

2(z-5)-(4z-4)-(-3z)=0

We multiply parentheses

2z-(4z-4)-(-3z)-10=0

We get rid of parentheses

2z-4z+3z+4-10=0

We add all the numbers together, and all the variables

z-6=0

We move all terms containing z to the left, all other terms to the right

z=6

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