3(k-9)-(6-2k)=4k

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Solution for 3(k-9)-(6-2k)=4k equation: 



3(k-9)-(6-2k)=4k

We move all terms to the left:

3(k-9)-(6-2k)-(4k)=0

We add all the numbers together, and all the variables

3(k-9)-(-2k+6)-4k=0

We add all the numbers together, and all the variables

-4k+3(k-9)-(-2k+6)=0

We multiply parentheses

-4k+3k-(-2k+6)-27=0

We get rid of parentheses

-4k+3k+2k-6-27=0

We add all the numbers together, and all the variables

k-33=0

We move all terms containing k to the left, all other terms to the right

k=33

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