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2(z+6)=2(z-3)
We move all terms to the left:
2(z+6)-(2(z-3))=0
We multiply parentheses
2z-(2(z-3))+12=0
We calculate terms in parentheses: -(2(z-3)), so:We get rid of parentheses
2(z-3)
We multiply parentheses
2z-6
Back to the equation:
-(2z-6)
2z-2z+6+12=0
We add all the numbers together, and all the variables
18!=0
There is no solution for this equation
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