2(z+4)=3z-6

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Solution for 2(z+4)=3z-6 equation: 



2(z+4)=3z-6

We move all terms to the left:

2(z+4)-(3z-6)=0

We multiply parentheses

2z-(3z-6)+8=0

We get rid of parentheses

2z-3z+6+8=0

We add all the numbers together, and all the variables

-1z+14=0

We move all terms containing z to the left, all other terms to the right

-z=-14

z=-14/-1

z=+14

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