5(4x+10)+5(2x-5)=(x-90)

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Solution for 5(4x+10)+5(2x-5)=(x-90) equation: 



5(4x+10)+5(2x-5)=(x-90)

We move all terms to the left:

5(4x+10)+5(2x-5)-((x-90))=0

We multiply parentheses

20x+10x-((x-90))+50-25=0



We calculate terms in parentheses: -((x-90)), so:

(x-90)

We get rid of parentheses

x-90

Back to the equation:

-(x-90)



We add all the numbers together, and all the variables

30x-(x-90)+25=0

We get rid of parentheses

30x-x+90+25=0

We add all the numbers together, and all the variables

29x+115=0

We move all terms containing x to the left, all other terms to the right

29x=-115

x=-115/29

x=-3+28/29

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