2(z+4)=2(3z-4)

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Solution for 2(z+4)=2(3z-4) equation: 



2(z+4)=2(3z-4)

We move all terms to the left:

2(z+4)-(2(3z-4))=0

We multiply parentheses

2z-(2(3z-4))+8=0



We calculate terms in parentheses: -(2(3z-4)), so:

2(3z-4)

We multiply parentheses

6z-8

Back to the equation:

-(6z-8)



We get rid of parentheses

2z-6z+8+8=0

We add all the numbers together, and all the variables

-4z+16=0

We move all terms containing z to the left, all other terms to the right

-4z=-16

z=-16/-4

z=+4

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