2(z+3)-3z=7*z+1)+15

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Solution for 2(z+3)-3z=7*z+1)+15 equation: 



2(z+3)-3z=7z+1)+15

We move all terms to the left:

2(z+3)-3z-(7z+1)+15)=0

We add all the numbers together, and all the variables

-3z+2(z+3)-(7z+1)=0

We multiply parentheses

-3z+2z-(7z+1)+6=0

We get rid of parentheses

-3z+2z-7z-1+6=0

We add all the numbers together, and all the variables

-8z+5=0

We move all terms containing z to the left, all other terms to the right

-8z=-5

z=-5/-8

z=5/8

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