7c-2(3-c)=4(c+2)

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Solution for 7c-2(3-c)=4(c+2) equation: 



7c-2(3-c)=4(c+2)

We move all terms to the left:

7c-2(3-c)-(4(c+2))=0

We add all the numbers together, and all the variables

7c-2(-1c+3)-(4(c+2))=0

We multiply parentheses

7c+2c-(4(c+2))-6=0



We calculate terms in parentheses: -(4(c+2)), so:

4(c+2)

We multiply parentheses

4c+8

Back to the equation:

-(4c+8)



We add all the numbers together, and all the variables

9c-(4c+8)-6=0

We get rid of parentheses

9c-4c-8-6=0

We add all the numbers together, and all the variables

5c-14=0

We move all terms containing c to the left, all other terms to the right

5c=14

c=14/5

c=2+4/5

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