2(y-5)-7=-5(-4y+1)-3y

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Solution for 2(y-5)-7=-5(-4y+1)-3y equation: 



2(y-5)-7=-5(-4y+1)-3y

We move all terms to the left:

2(y-5)-7-(-5(-4y+1)-3y)=0

We multiply parentheses

2y-(-5(-4y+1)-3y)-10-7=0



We calculate terms in parentheses: -(-5(-4y+1)-3y), so:

-5(-4y+1)-3y

We add all the numbers together, and all the variables

-3y-5(-4y+1)

We multiply parentheses

-3y+20y-5

We add all the numbers together, and all the variables

17y-5

Back to the equation:

-(17y-5)



We add all the numbers together, and all the variables

2y-(17y-5)-17=0

We get rid of parentheses

2y-17y+5-17=0

We add all the numbers together, and all the variables

-15y-12=0

We move all terms containing y to the left, all other terms to the right

-15y=12

y=12/-15

y=-4/5

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