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6(x+1)=-7(1+x)
We move all terms to the left:
6(x+1)-(-7(1+x))=0
We add all the numbers together, and all the variables
6(x+1)-(-7(x+1))=0
We multiply parentheses
6x-(-7(x+1))+6=0
We calculate terms in parentheses: -(-7(x+1)), so:We get rid of parentheses
-7(x+1)
We multiply parentheses
-7x-7
Back to the equation:
-(-7x-7)
6x+7x+7+6=0
We add all the numbers together, and all the variables
13x+13=0
We move all terms containing x to the left, all other terms to the right
13x=-13
x=-13/13
x=-1
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