2(y-4)=4y+4-4(-4y-1)

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Solution for 2(y-4)=4y+4-4(-4y-1) equation: 



2(y-4)=4y+4-4(-4y-1)

We move all terms to the left:

2(y-4)-(4y+4-4(-4y-1))=0

We multiply parentheses

2y-(4y+4-4(-4y-1))-8=0



We calculate terms in parentheses: -(4y+4-4(-4y-1)), so:

4y+4-4(-4y-1)

determiningTheFunctionDomain
4y-4(-4y-1)+4

We multiply parentheses

4y+16y+4+4

We add all the numbers together, and all the variables

20y+8

Back to the equation:

-(20y+8)



We get rid of parentheses

2y-20y-8-8=0

We add all the numbers together, and all the variables

-18y-16=0

We move all terms containing y to the left, all other terms to the right

-18y=16

y=16/-18

y=-8/9

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