y-6+3(4y+7)=-3(y+1)

Solution for y-6+3(4y+7)=-3(y+1) equation:

y-6+3(4y+7)=-3(y+1)

We move all terms to the left:

y-6+3(4y+7)-(-3(y+1))=0

We multiply parentheses

y+12y-(-3(y+1))+21-6=0


We calculate terms in parentheses: -(-3(y+1)), so:

-3(y+1)

We multiply parentheses

-3y-3

Back to the equation:

-(-3y-3)


We add all the numbers together, and all the variables

13y-(-3y-3)+15=0

We get rid of parentheses

13y+3y+3+15=0

We add all the numbers together, and all the variables

16y+18=0

We move all terms containing y to the left, all other terms to the right

16y=-18

y=-18/16

y=-1+1/8