2(y-4)-8y=28

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Solution for 2(y-4)-8y=28 equation: 



2(y-4)-8y=28

We move all terms to the left:

2(y-4)-8y-(28)=0

We add all the numbers together, and all the variables

-8y+2(y-4)-28=0

We multiply parentheses

-8y+2y-8-28=0

We add all the numbers together, and all the variables

-6y-36=0

We move all terms containing y to the left, all other terms to the right

-6y=36

y=36/-6

y=-6

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