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3(x-1)+3=9-(2x+1)
We move all terms to the left:
3(x-1)+3-(9-(2x+1))=0
We multiply parentheses
3x-(9-(2x+1))-3+3=0
We calculate terms in parentheses: -(9-(2x+1)), so:We add all the numbers together, and all the variables
9-(2x+1)
determiningTheFunctionDomain -(2x+1)+9
We get rid of parentheses
-2x-1+9
We add all the numbers together, and all the variables
-2x+8
Back to the equation:
-(-2x+8)
3x-(-2x+8)=0
We get rid of parentheses
3x+2x-8=0
We add all the numbers together, and all the variables
5x-8=0
We move all terms containing x to the left, all other terms to the right
5x=8
x=8/5
x=1+3/5
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