2(y-3)-4(y-2)=5y+6+6(y-7)

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Solution for 2(y-3)-4(y-2)=5y+6+6(y-7) equation: 



2(y-3)-4(y-2)=5y+6+6(y-7)

We move all terms to the left:

2(y-3)-4(y-2)-(5y+6+6(y-7))=0

We multiply parentheses

2y-4y-(5y+6+6(y-7))-6+8=0



We calculate terms in parentheses: -(5y+6+6(y-7)), so:

5y+6+6(y-7)

determiningTheFunctionDomain
5y+6(y-7)+6

We multiply parentheses

5y+6y-42+6

We add all the numbers together, and all the variables

11y-36

Back to the equation:

-(11y-36)



We add all the numbers together, and all the variables

-2y-(11y-36)+2=0

We get rid of parentheses

-2y-11y+36+2=0

We add all the numbers together, and all the variables

-13y+38=0

We move all terms containing y to the left, all other terms to the right

-13y=-38

y=-38/-13

y=2+12/13

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