6(2u+1)=u-5

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Solution for 6(2u+1)=u-5 equation: 



6(2u+1)=u-5

We move all terms to the left:

6(2u+1)-(u-5)=0

We multiply parentheses

12u-(u-5)+6=0

We get rid of parentheses

12u-u+5+6=0

We add all the numbers together, and all the variables

11u+11=0

We move all terms containing u to the left, all other terms to the right

11u=-11

u=-11/11

u=-1

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