2(y-1)-2=-2(-2y+3)-6y

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Solution for 2(y-1)-2=-2(-2y+3)-6y equation: 



2(y-1)-2=-2(-2y+3)-6y

We move all terms to the left:

2(y-1)-2-(-2(-2y+3)-6y)=0

We multiply parentheses

2y-(-2(-2y+3)-6y)-2-2=0



We calculate terms in parentheses: -(-2(-2y+3)-6y), so:

-2(-2y+3)-6y

We add all the numbers together, and all the variables

-6y-2(-2y+3)

We multiply parentheses

-6y+4y-6

We add all the numbers together, and all the variables

-2y-6

Back to the equation:

-(-2y-6)



We add all the numbers together, and all the variables

2y-(-2y-6)-4=0

We get rid of parentheses

2y+2y+6-4=0

We add all the numbers together, and all the variables

4y+2=0

We move all terms containing y to the left, all other terms to the right

4y=-2

y=-2/4

y=-1/2

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