2(y-1)+4y=3(y-1)+1

Solution for 2(y-1)+4y=3(y-1)+1 equation:

2(y-1)+4y=3(y-1)+1

We move all terms to the left:

2(y-1)+4y-(3(y-1)+1)=0

We add all the numbers together, and all the variables

4y+2(y-1)-(3(y-1)+1)=0

We multiply parentheses

4y+2y-(3(y-1)+1)-2=0


We calculate terms in parentheses: -(3(y-1)+1), so:

3(y-1)+1

We multiply parentheses

3y-3+1

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)


We add all the numbers together, and all the variables

6y-(3y-2)-2=0

We get rid of parentheses

6y-3y+2-2=0

We add all the numbers together, and all the variables

3y=0

y=0/3

y=0