2(y+7)-34=4y-11y+4(y-1)

Solution for 2(y+7)-34=4y-11y+4(y-1) equation:

2(y+7)-34=4y-11y+4(y-1)

We move all terms to the left:

2(y+7)-34-(4y-11y+4(y-1))=0

We multiply parentheses

2y-(4y-11y+4(y-1))+14-34=0


We calculate terms in parentheses: -(4y-11y+4(y-1)), so:

4y-11y+4(y-1)

We add all the numbers together, and all the variables

-7y+4(y-1)

We multiply parentheses

-7y+4y-4

We add all the numbers together, and all the variables

-3y-4

Back to the equation:

-(-3y-4)


We add all the numbers together, and all the variables

2y-(-3y-4)-20=0

We get rid of parentheses

2y+3y+4-20=0

We add all the numbers together, and all the variables

5y-16=0

We move all terms containing y to the left, all other terms to the right

5y=16

y=16/5

y=3+1/5