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(x+4)(6x-5)=0
We multiply parentheses ..
(+6x^2-5x+24x-20)=0
We get rid of parentheses
6x^2-5x+24x-20=0
We add all the numbers together, and all the variables
6x^2+19x-20=0
a = 6; b = 19; c = -20;
Δ = b2-4ac
Δ = 192-4·6·(-20)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-29}{2*6}=\frac{-48}{12} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+29}{2*6}=\frac{10}{12} =5/6 $
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