2(y+4)+3(y-3)=10

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Solution for 2(y+4)+3(y-3)=10 equation:



2(y+4)+3(y-3)=10
We move all terms to the left:
2(y+4)+3(y-3)-(10)=0
We multiply parentheses
2y+3y+8-9-10=0
We add all the numbers together, and all the variables
5y-11=0
We move all terms containing y to the left, all other terms to the right
5y=11
y=11/5
y=2+1/5

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