2(y+3)=4(y-1)

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Solution for 2(y+3)=4(y-1) equation: 



2(y+3)=4(y-1)

We move all terms to the left:

2(y+3)-(4(y-1))=0

We multiply parentheses

2y-(4(y-1))+6=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We get rid of parentheses

2y-4y+4+6=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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