2(y+2)=3(y+5)

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Solution for 2(y+2)=3(y+5) equation:



2(y+2)=3(y+5)
We move all terms to the left:
2(y+2)-(3(y+5))=0
We multiply parentheses
2y-(3(y+5))+4=0
We calculate terms in parentheses: -(3(y+5)), so:
3(y+5)
We multiply parentheses
3y+15
Back to the equation:
-(3y+15)
We get rid of parentheses
2y-3y-15+4=0
We add all the numbers together, and all the variables
-1y-11=0
We move all terms containing y to the left, all other terms to the right
-y=11
y=11/-1
y=-11

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