2(y+2)-3(y-3)=5(2y-4)

Solution for 2(y+2)-3(y-3)=5(2y-4) equation:

2(y+2)-3(y-3)=5(2y-4)

We move all terms to the left:

2(y+2)-3(y-3)-(5(2y-4))=0

We multiply parentheses

2y-3y-(5(2y-4))+4+9=0


We calculate terms in parentheses: -(5(2y-4)), so:

5(2y-4)

We multiply parentheses

10y-20

Back to the equation:

-(10y-20)


We add all the numbers together, and all the variables

-1y-(10y-20)+13=0

We get rid of parentheses

-1y-10y+20+13=0

We add all the numbers together, and all the variables

-11y+33=0

We move all terms containing y to the left, all other terms to the right

-11y=-33

y=-33/-11

y=+3