5+z-3(z-2)=4z-1

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Solution for 5+z-3(z-2)=4z-1 equation: 



5+z-3(z-2)=4z-1

We move all terms to the left:

5+z-3(z-2)-(4z-1)=0

We multiply parentheses

z-3z-(4z-1)+6+5=0

We get rid of parentheses

z-3z-4z+1+6+5=0

We add all the numbers together, and all the variables

-6z+12=0

We move all terms containing z to the left, all other terms to the right

-6z=-12

z=-12/-6

z=+2

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