2(y+2)+y=3(y-1)=6

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Solution for 2(y+2)+y=3(y-1)=6 equation: 



2(y+2)+y=3(y-1)=6

We move all terms to the left:

2(y+2)+y-(3(y-1))=0

We add all the numbers together, and all the variables

y+2(y+2)-(3(y-1))=0

We multiply parentheses

y+2y-(3(y-1))+4=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

3y-(3y-3)+4=0

We get rid of parentheses

3y-3y+3+4=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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