7x+12-4x=3(x+4)

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Solution for 7x+12-4x=3(x+4) equation: 



7x+12-4x=3(x+4)

We move all terms to the left:

7x+12-4x-(3(x+4))=0

We add all the numbers together, and all the variables

3x-(3(x+4))+12=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

3x-3x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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