2(y+2)+4y=22

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Solution for 2(y+2)+4y=22 equation: 



2(y+2)+4y=22

We move all terms to the left:

2(y+2)+4y-(22)=0

We add all the numbers together, and all the variables

4y+2(y+2)-22=0

We multiply parentheses

4y+2y+4-22=0

We add all the numbers together, and all the variables

6y-18=0

We move all terms containing y to the left, all other terms to the right

6y=18

y=18/6

y=3

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