(X+3)/5=(x-7)/10

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Solution for (X+3)/5=(x-7)/10 equation: 



(X+3)/5=(X-7)/10

We move all terms to the left:

(X+3)/5-((X-7)/10)=0

We calculate fractions


X/()+(-((X-7)*5)/()=0



We calculate terms in parentheses: +(-((X-7)*5)/(), so:

-((X-7)*5)/(

We multiply all the terms by the denominator


-((X-7)*5)



We calculate terms in parentheses: -((X-7)*5), so:

(X-7)*5

We multiply parentheses

5X-35

Back to the equation:

-(5X-35)



We get rid of parentheses

-5X+35

Back to the equation:

+(-5X+35)



We get rid of parentheses

X/()-5X+35=0

We multiply all the terms by the denominator


X-5X*()+35*()=0

We add all the numbers together, and all the variables

X-5X*()=0

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