2(y+2)+4y=2(4y+3)+8

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Solution for 2(y+2)+4y=2(4y+3)+8 equation: 



2(y+2)+4y=2(4y+3)+8

We move all terms to the left:

2(y+2)+4y-(2(4y+3)+8)=0

We add all the numbers together, and all the variables

4y+2(y+2)-(2(4y+3)+8)=0

We multiply parentheses

4y+2y-(2(4y+3)+8)+4=0



We calculate terms in parentheses: -(2(4y+3)+8), so:

2(4y+3)+8

We multiply parentheses

8y+6+8

We add all the numbers together, and all the variables

8y+14

Back to the equation:

-(8y+14)



We add all the numbers together, and all the variables

6y-(8y+14)+4=0

We get rid of parentheses

6y-8y-14+4=0

We add all the numbers together, and all the variables

-2y-10=0

We move all terms containing y to the left, all other terms to the right

-2y=10

y=10/-2

y=-5

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