10(9-x)+x+27=10x+(9-x)

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Solution for 10(9-x)+x+27=10x+(9-x) equation: 



10(9-x)+x+27=10x+(9-x)

We move all terms to the left:

10(9-x)+x+27-(10x+(9-x))=0

We add all the numbers together, and all the variables

10(-1x+9)+x-(10x+(-1x+9))+27=0

We add all the numbers together, and all the variables

x+10(-1x+9)-(10x+(-1x+9))+27=0

We multiply parentheses

x-10x-(10x+(-1x+9))+90+27=0



We calculate terms in parentheses: -(10x+(-1x+9)), so:

10x+(-1x+9)

We get rid of parentheses

10x-1x+9

We add all the numbers together, and all the variables

9x+9

Back to the equation:

-(9x+9)



We add all the numbers together, and all the variables

-9x-(9x+9)+117=0

We get rid of parentheses

-9x-9x-9+117=0

We add all the numbers together, and all the variables

-18x+108=0

We move all terms containing x to the left, all other terms to the right

-18x=-108

x=-108/-18

x=+6

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