2(y+10)=3y-1

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Solution for 2(y+10)=3y-1 equation: 



2(y+10)=3y-1

We move all terms to the left:

2(y+10)-(3y-1)=0

We multiply parentheses

2y-(3y-1)+20=0

We get rid of parentheses

2y-3y+1+20=0

We add all the numbers together, and all the variables

-1y+21=0

We move all terms containing y to the left, all other terms to the right

-y=-21

y=-21/-1

y=+21

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