2(y+1)=y+8+3y

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Solution for 2(y+1)=y+8+3y equation: 



2(y+1)=y+8+3y

We move all terms to the left:

2(y+1)-(y+8+3y)=0

We add all the numbers together, and all the variables

2(y+1)-(4y+8)=0

We multiply parentheses

2y-(4y+8)+2=0

We get rid of parentheses

2y-4y-8+2=0

We add all the numbers together, and all the variables

-2y-6=0

We move all terms containing y to the left, all other terms to the right

-2y=6

y=6/-2

y=-3

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